With the "test" becoming less strict from population A to population B.

#include <stdio.h>
#include <stdlib.h>
#define R2 66.80
#define R3 61.80
#define LOOP 100
#define R2_TRIALS 80
#define R3_TRIALS 50

float pPlay_trial(float pRate, int nCycle);

int main(void)
{
    int i;
    int nAnomaly=0;

    for (i=0; i < LOOP; i++)
    {
  float pR2;
  float pR3;
  pR2=pPlay_trial(R2,R2_TRIALS);
  pR3=pPlay_trial(R3,R3_TRIALS);

  if (pR2 < pR3 || pR2 == pR3)
      nAnomaly++;
    }

    printf("%f\n", ((float)nAnomaly)/LOOP);

    return 0;
}

float pPlay_trial(float pRate, int nCycle)
{
    int r3[nCycle];
    int i;
    int nSuccess=0;

    for (i=0; i < nCycle; i++) 
    {
  r3[i] = rand() % 100;
  //printf("%02d\n",r3[i]);
  if (r3[i] < pRate || r3[i] == pRate)
  {
      nSuccess++;
  }
    }
    return ((float)nSuccess)*100/nCycle;
}

OK. There's this game I play, in which you can acquire skill points when you gain an experience level. If you accumulate a certain required number of skill points, you can gain/strengthen a skill.

After a lot of hard work, I saved up enough skill points to advance in magical music.

If I succeed in playing magical music, I record the effect, in numbers. If I fail, I record 0. All samples are sequential, with nothing left out.

Set A was sampled when I was rank 3, the third highest rank when it comes to magical music. Set B was sampled right after I became rank 2. Now that my rank is now higher, I expect my success rate to be higher.

I thought I did, but now that you mention it, I'm not sure.

What happens if you assume that the populations are roughly Gaussian? With the "test" becoming less strict from population A to population B.
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