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Topic: %path% w/out the filename? (Read 2084 times) previous topic - next topic
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%path% w/out the filename?

hi, i cant find how to get the directory structure without the filename.  i have a file with path:
C:\music\new\songone.mp3
i need
C:\music\new
in my copy command.

btw, i've seen there is some new tagz (like $tracknumber()) is there a new help file?

thanks for your time,

%path% w/out the filename?

Reply #1 –
Code: [Select]
$replace(%_path_raw%,%_filename_ext%,)


Should do the tick for what you want to achieve.

%path% w/out the filename?

Reply #2 –
ahhh  just about, actually i just need_path
Code: [Select]
$replace(%_path%,%_filename_ext%,)

the path_raw gives me file://C:\_music\new\

but, yeah, thanks, that did the
Quote
tick

<G>

%path% w/out the filename?

Reply #3 –
If you want it without the file:// (or http://, or whatever) use %_path% instead.

%path% w/out the filename?

Reply #4 –
juglesh, a while ago I made some copy command script and posted it here. Maybe try a forum search for "copy command AND rar" if possible (maybe "rar" is too short). It was a script to copy and extract files from archives.

That script handled the directories I think, give it a try.

Have fun with it if you find it
Life is Real...
(But not in audio :) )