Passive bi-amping with AVR
Reply #32 – 2015-06-01 15:56:18
Sorry, I'm not an EE, so I may use the terms incorrectly. Isn't drive voltage and voltage swing sort of the same thing? No, not at all. Voltage drive tells you, that the amp behaves like a voltage source. Let's say 1V at the input leads to 2V at the amp's output (due to gain and volume control position). With a voltage source it doesn't matter if you connect a 4, 8, or 1000 ohm load - it will output 2V across that load. (I=V/R, so currents in the most simple case would be 0.5A, 0.25A, 0.002A) Output voltage swing tells you the range of voltage that the amp can produce, which is usually a bit lower than the supply voltages. Let's say the power supply provides +/-5V and the amplifier can output up to +/-4V. So we have Vpp (voltage peak-to-peak) = 8V, Vp (voltage peak) = 4V, Vrms (root mean square) = 2.828VIf I say that someone does not listen loud enough to make use of the excess current available then I mean there is insufficient drive voltage, or voltage swing from the amp to force the amp to supply the extra current, but again, if I'm using the terms incorrectly here then please correct me. As you turn up the volume control, you turn up the output voltage. The "right amount" of current is drawn automatically by the load. Low current does not mean insufficient anything, but just a high load resistance for a given output voltage. None of these numbers will tell you how loud the speaker will play. For that you need to include the sensitivity or efficiency.